2x^2-20x=22

Solution for 2x^2-20x=22 equation:

2x^2-20x=22

We move all terms to the left:

2x^2-20x-(22)=0

a = 2; b = -20; c = -22;
Δ = b2-4ac
Δ = -202-4·2·(-22)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-24}{2*2}=\frac{-4}{4}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+24}{2*2}=\frac{44}{4}
=11
$